Mathématiques

Question

Bonjour je m'excuse mais le devoirs n'est pas fini il me faut encore:
•(x-2)²=
•(1-3x)²=
•(2x-1)²=
•(3-5x)²=
•(4x-3)²=
•4-3x)²=
•(x+2)(x-2)
•(x+3)(x-3)
•(3x-1)(3x+1)
•(2x+1)(2x-1)
•(5+3x)(x-3)
•(3x-2)(3x+2)
•(3+4x)(3-4x)
•(4x²+3)(4x²-3)
Je vous en prie merci.

1 Réponse

  • •(x-2)²
    =x²-2²
    =x²-4

    •(1-3x)²
    =1-(3x)²
    =1-9x²

    •(2x-1)²
    =(2x)²-1
    =4x²-1

    •(3-5x)²
    =3²-(5x)²
    =9-25x²

    •(4x-3)²
    =(4x)²-3²
    =16x²-9

    •(4-3x)²
    =4²-(3x)²
    =16-9x²

    •(x+2)(x-2)
    =x²-2²
    =x²-4

    •(x+3)(x-3)
    =x²-3²
    =x²-9

    •(3x-1)(3x+1)
    =(3x)²-1²
    =9x²-1

    •(2x+1)(2x-1)
    =(2x)²-1²
    =4x²-1

    •(5+3x)(x-3)

    •(3x-2)(3x+2)
    =(3x)²-2²
    =9x²-4

    •(3+4x)(3-4x)
    =3²-(4x)²
    =9-16x²

    •(4x²+3)(4x²-3)
    =(4x²)²-3²
    =16[tex] x^{4}[/tex]-9

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